Latro
07-11-2011, 05:20 PM
Do any of you do WCs by simultaneously adding and removing water? I was noticing one of my fish, the smallest one, was swimming badly (away from equilibrium significantly), and then when doing a largeish WC (in which I noticed higher than usual amounts of food and poop; I may need to go BB, heh) I noticed some of my other fish were hiding and darkening, more than usual.
So I set up another hose to add water at the same time; they seemed to appreciate the clean water being added even as water was removed, and two of them even went under the hose. Do you find that this works well? Do you encounter any problems with it?
Incidentally, I did a little math, and purely from the perspective of concentration, you would have to move the same volume of water as about a 70% WC to get a net change in concentration (of something in the tank and not in the input water) equivalent to a 50% WC. (Assuming the flow rates of your two hoses are exactly equal; the math becomes messier, albeit still doable, if they are different). In general, an x% WC would require 100*(ln(100)-ln(100-x))% of your volume of water to be moved in this way; for example, a 75% change would require moving about 140% of your volume of water (you can see that this becomes impractical as x gets especially large, and in fact becomes infinite as x goes to 100). I suppose someone might be interested in this...
(By the way, in units of fractions, where x=1 is the equivalent of a 100% WC, you just get -ln(1-x) at the end, which is a much simpler expression.)
So I set up another hose to add water at the same time; they seemed to appreciate the clean water being added even as water was removed, and two of them even went under the hose. Do you find that this works well? Do you encounter any problems with it?
Incidentally, I did a little math, and purely from the perspective of concentration, you would have to move the same volume of water as about a 70% WC to get a net change in concentration (of something in the tank and not in the input water) equivalent to a 50% WC. (Assuming the flow rates of your two hoses are exactly equal; the math becomes messier, albeit still doable, if they are different). In general, an x% WC would require 100*(ln(100)-ln(100-x))% of your volume of water to be moved in this way; for example, a 75% change would require moving about 140% of your volume of water (you can see that this becomes impractical as x gets especially large, and in fact becomes infinite as x goes to 100). I suppose someone might be interested in this...
(By the way, in units of fractions, where x=1 is the equivalent of a 100% WC, you just get -ln(1-x) at the end, which is a much simpler expression.)